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Pass Guaranteed 2025 AEE High-quality CEM: New Certified Energy Manager (CEM) Dumps Ppt

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Our Certified Energy Manager (CEM) (CEM) practice exam simulator mirrors the Certified Energy Manager (CEM) (CEM) exam experience, so you know what to anticipate on Certified Energy Manager (CEM) (CEM) certification exam day. Our AEE CEM Practice Test software features various question styles and levels, so you can customize your AEE CEM exam questions preparation to meet your needs.

AEE Certified Energy Manager (CEM) Sample Questions (Q46-Q51):

NEW QUESTION # 46
A high-pressure steam system passes 180°C condensate (saturated liquid) through a steam trap to an atmospherically vented condensate receiver tank. If the steam trap is working properly, how much of the condensate mass can be lost out the vent of the receiver tank in the form of flash steam?

A. 6%
B. 100%
C. 15%
D. 25%
E. 66%

Answer: D

NEW QUESTION # 47
In a PID control system, what is the purpose of the Proportional Gain?

A. Senses high load rate
B. Reacts to change
C. Reduces/eliminates offset
D. Control point

Answer: B

NEW QUESTION # 48
For general indoor residential lighting applications, which light source can provide the most appropriate illumination with the highest efficacy?

A. Light-emitting diode (LED)
B. Mercury vapor (MV)
C. Compact fluorescent (CFL)
D. Low-pressure sodium (LPS)
E. Incandescent

Answer: A

NEW QUESTION # 49
A 50-kW induction motor (1,500 rpm synchronous speed) has a nameplate full-load rotational speed of 1,455 rpm. Field measurements show the actual rotational speed is 1,475 rpm. Using the slip method, calculate the partial load factor of the motor.

A. 80%
B. 56%
C. 46%
D. 98%
E. 101%

Answer: A

NEW QUESTION # 50
Why do electric utility companies transmit power at high voltages?
SELECT THE CORRECT ANSWER

A. Higher voltages are more stable
B. Higher voltages are safer
C. Electrical frequency is more stable
D. Transmission power losses (12R) are less

Answer: D

Explanation:
Electric utility companies transmit power at high voltages primarily to reduce transmission power losses, which are proportional to the square of the current (I²) multiplied by the resistance (R) of the transmission lines. This relationship is expressed by the formula for power loss: P_loss = I²R.
Key Points:
* Power Loss and Current Relationship:Power losses in transmission lines are directly proportional to the square of the current flowing through them. Reducing the current decreases these losses significantly.
* High Voltage Transmission:By increasing the transmission voltage, the current required to deliver the same amount of power decreases. This is because power (P) is the product of voltage (V) and current (I): P = VI. For a given power level, increasing voltage allows for a corresponding decrease in current.
* Reduced I²R Losses:Lower current results in reduced I²R losses, enhancing the efficiency of power transmission over long distances.
Conclusion:
Transmitting power at high voltages minimizes transmission losses, making it the most efficient method for long-distance electrical power delivery. Therefore, the correct answer is C. Transmission power losses (I²R) are less.

NEW QUESTION # 51
......

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